The pie given below shows the total population in five cities (A, B, C, D, E).

In city F, the population of males is 50% more than the total population in D and female population is 20% less than the average population of B and E. Find the total population of F (male + females) is what percentage of total population of C?

The correct answer is 152.5%.

Step 1: Determine the value of $p$ and population of each city
From the given pie chart, the total population is 1200, distributed among cities A, B, C, D, and E as follows:
• City A = $(2p+5)\%$
• City B = 8%
• City C = $p\%$
• City D = 15%
• City E = 12%

Since the total percentage of a pie chart is equal to 100%:

$(2p+5)+8+p+15+12=100$

$3p+40=100$

$3p=60$

$p=20$

Thus, the population percentage of City C is $p\%=20\%$.

Population of City C:

$\text{Population of C}=20\%\text{of}1200=\frac{20}{100}\times 1200=240$

Step 2: Find the male population in City F
Population of City D = 15% of 1200:

$\text{Population of D}=\frac{15}{100}\times 1200=180$

The male population of F is 50% more than the total population in D:

$\text{Male population of F}=180+(50\%\text{of}180)=180+90=270$

Step 3: Find the female population in City F
Population of City B = 8% of 1200 = 96
Population of City E = 12% of 1200 = 144

Average population of cities B and E:

$\text{Average of B and E}=\frac{96+144}{2}=\frac{240}{2}=120$

The female population of F is 20% less than this average:

$\text{Female population of F}=120-(20\%\text{of}120)=120-24=96$

Step 4: Calculate the total population of City F

$\text{Total population of F}=270+96=366$

Step 5: Find what percentage the total population of F is of City C

$\text{Required Percentage}=\left(\frac{366}{240}\right)\times 100\%=152.5\%$