Question Details

The pie given below shows the total population in five cities (A, B, C, D, E).

The population of cities D and E is what percentage more/less than the total population of A and C

Options

A

53.20

B

58.46%

C

52.22%

D

54.30%

Show Answer

Correct Answer :

Option B

58.46%

58.46%

Solution :

Correct Answer: 58.46%

Based on the provided pie chart, the total population is 1200, distributed among five cities (A, B, C, D, E) with the following percentage values:
- City A: (2p + 5)%
- City B: 8%
- City C: p%
- City D: 15%
- City E: 12%

Step 1: Solve for p
Since the sum of all percentages in a pie chart must be equal to 100%, we write the equation:

( 2 p + 5 ) + 8 + p + 15 + 12 = 100

Combine the like terms:

3 p + 40 = 100

Subtract 40 from both sides:

3 p = 60

Divide by 3:

p = 20

Step 2: Find the percentage shares of the cities
Substitute the value of p = 20 back into the percentage expressions:
- Population percentage of A = 2(20) + 5 = 45%
- Population percentage of C = 20%
- Population percentage of D = 15%
- Population percentage of E = 12%

Step 3: Calculate the total percentages for the groups
- Total percentage of cities D and E:

15 % + 12 % = 27 %

- Total percentage of cities A and C:

45 % + 20% = 65%

Step 4: Calculate how much less the population of D and E is than A and C
The difference in percentage points is:

65 % - 27 % = 38 %

Now, find the percentage difference relative to the total of A and C:

Percentage Less = 38 65 × 100

Percentage Less 58.46 %

Thus, the population of cities D and E is 58.46% less than the total population of A and C.

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