The pie given below shows the total population in five cities (A, B, C, D, E).

Out of the total population of all the cities 35% are females and 55% of the total population of city D are females. Total females in all the cities except D is how many more/ less than total population of A.

From the given pie chart, the total population is 1200. First, we determine the value of $p$ by summing up the percentages of all five cities:

$(2p+5)+8+p+15+12=100$

Simplifying the equation:
$3p+40=100$
$3p=60$
$p=20$

Using $p=20$, we can find the population distribution for the relevant cities:
City A's percentage = $2\left(20\right)+5=45\%$
Total population of City A = $45\%\text{of}1200=0.45\times 1200=540$
Total population of City D = $15\%\text{of}1200=0.15\times 1200=180$

Next, we calculate the number of females:
Total females across all cities (35% of total population):
$\text{Total Females}=35\%\text{of}1200=0.35\times 1200=420$

Females in City D (55% of City D's population):
$\text{Females in D}=55\%\text{of}180=0.55\times 180=99$

Therefore, the total number of females in all cities except City D is:
$420-99=321$

To find how many more or less these females are compared to the total population of City A:
$\text{Difference}=540-321=219$

Thus, the total number of females in all cities except D is 219 less than the total population of A.

The correct option is 219.