The pie given below shows the total population in five cities (A, B, C, D, E).

In city F, the population of males is 50% more than the total population in D and female population is 20% less than the average population of B and E. Find the total population of F (male + females) is what percentage of total population of C?

Based on the pie chart provided in the image, the total population across five cities (A, B, C, D, and E) is 1200. The population distribution is given in percentages as follows:

• City A: $(2p+5)\%$
• City B: $8\%$
• City C: $p\%$
• City D: $15\%$
• City E: $12\%$

Step 1: Find the value of $p$
Since the sum of all percentages in a pie chart must equal 100%, we can set up the following equation:
$(2p+5)+8+p+15+12=100$
Simplifying the equation:
$3p+40=100$
$3p=60$
$p=20$

Using $p=20$, we can determine the percentages and populations of the relevant cities:

• City C: $p\%=20\%$ of 1200 = $0.20\times 1200=240$
• City D: $15\%$ of 1200 = $0.15\times 1200=180$
• City B: $8\%$ of 1200 = $0.08\times 1200=96$
• City E: $12\%$ of 1200 = $0.12\times 1200=144$

Step 2: Calculate the male population of city F
The male population of F is 50% more than the total population in D:
$\text{Males in F}=180\times (1+0.50)=180\times 1.5=270$

Step 3: Calculate the female population of city F
First, find the average population of B and E:
$\text{Average of B and E}=\frac{96+144}{2}=\frac{240}{2}=120$
The female population of F is 20% less than this average:
$\text{Females in F}=120\times (1-0.20)=120\times 0.80=96$

Step 4: Find the total population of city F
$\text{Total population of F}=\text{Males in F}+\text{Females in F}=270+96=366$

Step 5: Find what percentage the population of F is of the population of C
We divide the population of F by the population of C, and multiply by 100%:
$\text{Percentage}=\frac{366}{240}\times 100\%=1.525\times 100\%=152.5\%$

Thus, the total population of F is 152.5% of the total population of C.