The reagent(s) used in hydroboration oxidation of propene are

(A)B₂H₆

(B) H₂O

(C)H₂O₂

(D) OH⁻

Choose the correct answer from the options given below:

The correct option is (A), (B) and (C) only.

Hydroboration-oxidation is a two-step organic reaction that converts an alkene, such as propene, into an alcohol (specifically, propan-1-ol) via anti-Markovnikov addition of water across the double bond.

Let's break down the reagents involved in each step of the process:

1. Hydroboration Step:
In the first step, propene reacts with diborane ($B_2{H}_6$), which acts as a source of borane (${\mathrm{BH}}_3$). The boron atom adds to the less substituted carbon of the double bond, while a hydrogen atom adds to the more substituted carbon. This step leads to the formation of a trialkylborane intermediate. Therefore, (A) $B_2{H}_6$ is a required reagent.

2. Oxidation and Hydrolysis Step:
In the second step, the trialkylborane intermediate is oxidized and hydrolyzed to yield the final alcohol. This oxidation is carried out using hydrogen peroxide ((C) $H_2{O}_2$) in the presence of water ((B) $H_{2}O$) and an aqueous base (such as sodium hydroxide, which provides hydroxide ions, ${\mathrm{OH}}^{-}$).

Since the question asks for the primary chemical reagents representing the main components added for the conversion of the alkene to the alcohol in this reaction sequence, they are diborane, water, and hydrogen peroxide, corresponding to (A), (B), and (C) respectively.