The table below provides details regarding the number of men and women working at five distinct corporations (V, W, X, Y, and Z), along with the proportion of total personnel (men + women) who received a promotion at each corporation. Review the dataset to answer the question that follows.

Corporation	Men	Women	% of personnel promoted
V	400	350	40%
W	260	100	80%
X	340	410	60%
Y	200	300	80%
Z	240	360	50%

Note: The total staff size at any corporation is the sum of the men and women working there.

If 21% of the promoted staff at Z are over 50 years of age, then the promoted staff at Z who are 50 years old or younger are what percent less than the combined number of men employed at W and Z?

Correct Option: 52.6%

Step-by-step Solution:

Step 1: Calculate the total personnel and promoted staff at Corporation Z

From the given table, for Corporation Z:

Number of Men = 240

Number of Women = 360

Total personnel at Z = $240+360=600$

The table indicates that 50% of the total personnel at Z received a promotion.

Total promoted staff at Z = $50\%\text{ of }600=300$

Step 2: Find the promoted staff at Z who are 50 years old or younger

If 21% of the promoted staff at Z are over 50 years of age, then the percentage of promoted staff who are 50 years old or younger is:

$100\%-21\%=79\%$

Number of promoted staff at Z who are 50 years old or younger:

$79\%\text{ of }300=\frac{79}{100}\times 300=237$

Step 3: Calculate the combined number of men employed at W and Z

From the table:

Men employed at W = 260

Men employed at Z = 240

Combined number of men employed at W and Z = $260+240=500$

Step 4: Calculate the required percentage difference

We need to determine what percent 237 is less than 500:

Difference = $500-237=263$

Percentage less = $\left(\frac{263}{500}\right)\times 100=52.6\%$

Hence, the promoted staff at Z who are 50 years old or younger are 52.6% less than the combined number of men employed at W and Z.