The table below shows employees of a company in 5 different towns over the period of 5 years.
| Year | Town | ||||
|---|---|---|---|---|---|
| Hyderabad | Punjab | Pune | Kolkata | Delhi | |
| 2016 | 520 | 325 | 152 | 425 | 545 |
| 2017 | 680 | 475 | 250 | 765 | 645 |
| 2018 | 874 | 850 | 179 | 857 | 820 |
| 2019 | 745 | 780 | 375 | 856 | 765 |
| 2020 | 954 | 822 | 425 | 880 | 923 |
Note: All figures are fictitious.
Employees from Pune in 2018 are what per cent of the total employees of all towns together in that year?
Correct Answer :
5%
Solution :
The correct answer is 5%.
Let us find the percentage step-by-step:
1. First, identify the number of employees from Pune in the year 2018 from the table. Looking at the row for 2018 under the column Pune, the number of employees is:
Pune (2018) = 179
2. Next, calculate the total number of employees across all towns in 2018 by summing the values in the row corresponding to the year 2018:
Total (2018) = Hyderabad + Punjab + Pune + Kolkata + Delhi
Total (2018) = 874 + 850 + 179 + 857 + 820
Let's perform the addition:
874 + 850 = 1724
1724 + 179 = 1903
1903 + 857 = 2760
2760 + 820 = 3580
So, the total number of employees in all towns in 2018 is:
Total (2018) = 3580
3. Now, find what percent the employees from Pune (179) are of the total employees (3580) in 2018:
Percentage = (Employees from Pune / Total Employees) × 100
Simplifying the fraction:
(since 179 × 20 = 3580)
Therefore:
Percentage =
%
Thus, the employees from Pune in 2018 are 5% of the total employees of all towns together in that year.
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