The table given below shows the average number of articles (A, B and C) sold by Pesto company in three different months. It also shows the percentage of article A sold by Pesto company out of the total number of articles sold in these months. Table also reflects the total number of article C sold in these months. Read the table carefully and answer the following questions.

Months	Average number of articles sold	Percentage of article A sold	Total number of articles C sold
April	100	40%	100
May	120	30%	70
June	72	25%	80

Ratio of males to females who purchased total articles (A, B and C) in June is 3: 1 and the ratio of male to females who purchased articles A in June is 1: 2. If only 10 females purchased articles C in June, then find the number of males purchased articles B. (Note: All the articles are purchased from Pesto)

The correct answer is 74.

Let us break down the solution step-by-step based on the data provided in the table and the question details for the month of June.

Step 1: Calculate the total number of articles sold in June.
The table shows that for June, the average number of three articles (A, B, and C) sold is 72.
Since there are three articles (A, B, and C), the total number of articles sold in June is:
Total articles = Average × 3
Total articles = 72 × 3 = 216

Step 2: Calculate the number of article A sold in June.
The table states that the percentage of article A sold in June is 25% of the total number of articles sold in June.
Number of article A sold = 25% of 216
Number of article A sold = 216 / 4 = 54

Step 3: Calculate the number of article B sold in June.
The total number of articles sold is the sum of articles A, B, and C sold.
From the table, the total number of article C sold in June is 80.
Therefore, the number of article B sold in June is:
Number of article B sold = Total articles - (A + C)
Number of article B sold = 216 - (54 + 80) = 216 - 134 = 82

Step 4: Analyze the buyer distribution (males and females) in June.
The ratio of total males to females who purchased the articles in June is 3:1.
Let the number of males who purchased total articles be 3x and females be 1x.
Total purchasers = 3x + x = 4x
Since each purchased article corresponds to one purchaser (as implied by the question structure), the total purchasers equals the total articles purchased, which is 216.
4x = 216
x = 54
Total females who purchased articles in June = 54
Total males who purchased articles in June = 3 × 54 = 162

Step 5: Determine the gender breakdown for article A.
The ratio of males to females who purchased article A in June is 1:2.
Total purchasers of article A = 54
Let the number of males purchasing A be y and females be 2y.
y + 2y = 54
3y = 54
y = 18
Females who purchased article A = 2 × 18 = 36
Males who purchased article A = 18

Step 6: Determine the gender breakdown for article C.
The problem states that only 10 females purchased article C in June.
Since the total number of article C sold in June is 80:
Males who purchased article C = Total C - Females who purchased C
Males who purchased article C = 80 - 10 = 70

Step 7: Find the number of males who purchased article B.
The total number of males who purchased any article is the sum of males who purchased articles A, B, and C:
Total males = (Males who purchased A) + (Males who purchased B) + (Males who purchased C)
162 = 18 + (Males who purchased B) + 70
162 = 88 + (Males who purchased B)
Males who purchased B = 162 - 88 = 74