The table given below shows the average number of articles (A, B and C) sold by Pesto company in three different months. It also shows the percentage of article A sold by Pesto company out of the total number of articles sold in these months. Table also reflects the total number of article C sold in these months. Read the table carefully and answer the following questions.

Months	Average number of articles sold	Percentage of article A sold	Total number of articles C sold
April	100	40%	100
May	120	30%	70
June	72	25%	80

Find the ratio of the sum of the number of articles A and B together sold in May to the difference between the articles B and C sold in April.

The correct option is 29:2.

Let's break down the information given in the table and solve the problem step-by-step.

The table displays information about three types of articles (A, B, and C) sold by Pesto company over three months (April, May, and June).

For each month, let's denote:
Total number of articles sold = T
Average number of articles sold = Average of A, B, and C = T / 3
Therefore, the Total number of articles sold (T) in a month is 3 × (Average number of articles sold).

Step 1: Calculate the values for April
- The average number of articles sold in April is 100.
So, the total number of articles sold in April is:
$T=3\times 100=300$
- Percentage of article A sold is 40% of the total:
$A=40\%\text{ of }300=0.40\times 300=120$
- Total number of article C sold is 100.
- Since the total articles sold $T=A+B+C$, we can find the number of article B sold in April:
$B=T-(A+C)$
$B=300-(\mathrm{120}+\mathrm{100})=300-220=80$
Thus, for April: A = 120, B = 80, C = 100.

Step 2: Calculate the values for May
- The average number of articles sold in May is 120.
So, the total number of articles sold in May is:
$T=3\times 120=360$
- Percentage of article A sold is 30% of the total:
$A=30\%\text{ of }360=0.30\times 360=108$
- Total number of article C sold is 70.
- We can find the number of article B sold in May:
$B=T-(A+C)$
$B=360-(\mathrm{108}+\mathrm{70})=360-178=182$
Thus, for May: A = 108, B = 182, C = 70.

Step 3: Calculate the required ratio
The question asks for the ratio of:
(Sum of the number of articles A and B sold in May) to (Difference between articles B and C sold in April).
- Sum of A and B sold in May:
$A_{\text{May}}+B_{\text{May}}=108+182=290$
- Difference between B and C sold in April:
$|B_{\text{April}}-C_{\text{April}}|=|80-100|=20$
- Ratio:
$\text{Ratio}=\frac{290}{20}=\frac{29}{2}$
Therefore, the required ratio is 29:2.