The table given below shows the average number of articles (A, B and C) sold by Pesto company in three different months. It also shows the percentage of article A sold by Pesto company out of the total number of articles sold in these months. Table also reflects the total number of article C sold in these months. Read the table carefully and answer the following questions.

Months	Average number of articles sold	Percentage of article A sold	Total number of articles C sold
April	100	40%	100
May	120	30%	70
June	72	25%	80

In month of July, total number of articles A sold by Pesto are 25% more than the average number of articles B sold in the month of May and June. If the sum of the article B and C sold by Pesto in July are 30% more than the articles B sold by Pesto in April, then find the difference in the number of articles B sold in July to that of in April.

The correct option is Can’t be determined.

Let us analyze the given data step-by-step to find the number of articles sold in each month. Since the table lists the average number of three articles (A, B, and C) sold, the total number of articles sold in any month is given by:
$\mathrm{Total\; articles}=3\times \mathrm{Average\; number\; of\; articles\; sold}$
Using this relation, we can calculate the quantities of A, B, and C for April, May, and June.

1. Calculations for April:
Average sold = 100, which means:
$\mathrm{Total\; articles}=3\times 100=300$
Percentage of article A sold = 40% of the total:
$\mathrm{Articles\; A\; sold}=40\%of300=120$
Total number of article C sold = 100.
Now, we can find the number of articles B sold in April:
$\mathrm{Articles\; B\; sold}=\mathrm{Total}-(A+C)=300-(120+100)=80$

2. Calculations for May:
Average sold = 120, which means:
$\mathrm{Total\; articles}=3\times 120=360$
Percentage of article A sold = 30% of the total:
$\mathrm{Articles\; A\; sold}=30\%of360=108$
Total number of article C sold = 70.
Now, we can find the number of articles B sold in May:
$\mathrm{Articles\; B\; sold}=\mathrm{Total}-(A+C)=360-(108+70)=182$

3. Calculations for June:
Average sold = 72, which means:
$\mathrm{Total\; articles}=3\times 72=216$
Percentage of article A sold = 25% of the total:
$\mathrm{Articles\; A\; sold}=25\%of216=54$
Total number of article C sold = 80.
Now, we can find the number of articles B sold in June:
$\mathrm{Articles\; B\; sold}=\mathrm{Total}-(A+C)=216-(54+80)=82$

4. Calculations for July:
We are given that the sum of articles B and C sold by Pesto in July is 30% more than the articles B sold by Pesto in April.
Let $B_{\mathrm{July}}$ and $C_{\mathrm{July}}$ represent the number of articles B and C sold in July, respectively.
We have:
$B_{\mathrm{July}}+C_{\mathrm{July}}=1.30\times B_{\mathrm{April}}$
Substituting $B_{\mathrm{April}}=80$ into the equation:
$B_{\mathrm{July}}+C_{\mathrm{July}}=1.30\times 80=104$

We are asked to find the difference between the number of articles B sold in July ($B_{\mathrm{July}}$) and those sold in April ($B_{\mathrm{April}}=80$).
Since we only know the sum $B_{\mathrm{July}}+C_{\mathrm{July}}=104$ and there is no additional information provided to determine the individual value of $C_{\mathrm{July}}$, we cannot find the exact value of $B_{\mathrm{July}}$.
Therefore, the difference between the number of articles B sold in July and April cannot be determined.