The table given below shows the data about track record of car racing game, where 4 cars P, Q, R and S are competing to reach finishing line which is at a distance of 3000 m from their initial starting point.

1. Drift refers to over starting intentionally done by driver.
2. While calculating average speed, do not consider time taken in drift/crash.
3. Points = 50 × drifts – 20 × crashed

Cars	Drift	Time to reach finishing line (in sec)	Crash
P	5	180	3
Q	7	120	5
R	6	150	4
S	8	100	6

Speed of car S is what percentage more than that of car Q?

To find how much percentage more the speed of car S is compared to car Q, we first need to calculate the speeds of both cars.

The total distance to the finishing line for all cars is given as:
Distance = 3000 m

Step 1: Calculate the speed of Car Q
From the table, the time taken by Car Q to reach the finishing line is 120 seconds.
The speed of Car Q is calculated using the formula:

$\text{Speed of Q}=\frac{\text{Distance}}{\text{Time taken by Q}}$

$\text{Speed of Q}=\frac{3000}{120}=25\text{m/s}$

Step 2: Calculate the speed of Car S
From the table, the time taken by Car S to reach the finishing line is 100 seconds.
The speed of Car S is:

$\text{Speed of S}=\frac{\text{Distance}}{\text{Time taken by S}}$

$\text{Speed of S}=\frac{3000}{100}=30\text{m/s}$

Step 3: Calculate the percentage difference
We want to find by what percentage the speed of car S is more than that of car Q.
Difference in speed = Speed of S - Speed of Q = 30 m/s - 25 m/s = 5 m/s.
Percentage more is calculated with respect to the speed of car Q:

$\text{Percentage more}=\left(\frac{\text{Speed of S}-\text{Speed of Q}}{\text{Speed of Q}}\right)\times 100$

$\text{Percentage more}=\left(\frac{5}{25}\right)\times 100=20\%$

Therefore, the speed of car S is 20% more than that of car Q.