The table given below shows the data about track record of car racing game, where 4 cars P, Q, R and S are competing to reach finishing line which is at a distance of 3000 m from their initial starting point.

1. Drift refers to over starting intentionally done by driver.
2. While calculating average speed, do not consider time taken in drift/crash.
3. Points = 50 × drifts – 20 × crashed

Cars	Drift	Time to reach finishing line (in sec)	Crash
P	5	180	3
Q	7	120	5
R	6	150	4
S	8	100	6

In order to gain 10 more points than car S, how many total drifts should car P have made, if car P’s time and number of crashes remain same.

To find the total number of drifts car P needs to make to gain 10 more points than car S, let us first calculate the points scored by car S and the current points of car P using the given formula:
Points = 50 × drifts - 20 × crashes

First, we look at the data for Car S from the table:
• Drifts made by S = 8
• Crashes by S = 6
Now, we calculate the points for Car S:
Points for S = 50 × 8 - 20 × 6
Points for S = 400 - 120 = 280

The question states that car P wants to gain 10 more points than car S.
Therefore, the target points for Car P is:
Target Points for P = Points for S + 10
Target Points for P = 280 + 10 = 290

Next, let us look at the data for Car P:
• Number of crashes by P remains the same, which is 3 (from the table).
Let $d$ be the new total number of drifts car P needs to make.
Using the points formula for car P:
50 × $d$ - 20 × 3 = 290

Let us solve for $d$:
50 × $d$ - 60 = 290
50 × $d$ = 290 + 60
50 × $d$ = 350
$d$ = 350 / 50 = 7

Thus, car P should have made a total of 7 drifts.

Therefore, the correct option is 7.