The table given below shows the data about track record of car racing game, where 4 cars P, Q, R and S are competing to reach finishing line which is at a distance of 3000 m from their initial starting point.
1. Drift refers to over starting intentionally done by driver.
2. While calculating average speed, do not consider time taken in drift/crash.
3. Points = 50 × drifts – 20 × crashed
| Cars | Drift | Time to reach finishing line (in sec) | Crash |
|---|---|---|---|
| P | 5 | 180 | 3 |
| Q | 7 | 120 | 5 |
| R | 6 | 150 | 4 |
| S | 8 | 100 | 6 |
Another car named T, makes total number of drifts same as that of car R and it still receives 0 points at the end. How many crashes must car T have suffered?
Correct Answer :
15
Solution :
The correct answer is 15.
To find the number of crashes suffered by car T, we can use the formula provided for calculating points:
According to the given table, car R has 6 drifts. Since car T has the same number of drifts as car R, we have:
We are also given that car T receives 0 points at the end. We can set up the equation with the number of crashes represented by :
Now, we solve for :
Add to both sides of the equation:
Divide by 20:
Therefore, car T must have suffered 15 crashes.
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