The table given below shows the total number of red and blue balls in five different bags (A, B, C, D & E). it also shows the difference between red and blue balls and percentage of red balls with respect to total balls.

Total bags	Difference between red and blue balls	Percentage of red ball with respect to total balls
A	60	62.5%
B	198	66.5%
C	188	70%
D	76	60%
E	330	72%

The number of Red ball in A and E together is what percentage of number of blue balls in A and E together.

To find the relationship between the balls in bags A and E, we first calculate the total number of red and blue balls in each of these bags.

1. Analysis of Bag A:
We are given that the percentage of red balls in Bag A is 62.5%.
Therefore, the percentage of blue balls in Bag A is:

$100\%-62.5\%=37.5\%$

The difference in percentage between red and blue balls is:

$62.5\%-37.5\%=25\%$

We are given that the difference between red and blue balls is 60. Therefore, 25% of the total balls in Bag A equals 60.
Let $T_A$ be the total number of balls in Bag A:

$25\%\text{of}{T}_A=60$

$0.25\times T_A=60$

$T_A=\frac{60}{0.25}=240$

Now we calculate the individual counts of red and blue balls in Bag A:
Number of red balls in A ($R_A$):

$R_A=62.5\%\text{of}240=150$

Number of blue balls in A ($B_A$):

$B_A=240-150=90$

2. Analysis of Bag E:
We are given that the percentage of red balls in Bag E is 72%.
Therefore, the percentage of blue balls in Bag E is:

$100\%-72\%=28\%$

The difference in percentage between red and blue balls is:

$72\%-28\%=44\%$

We are given that the difference between red and blue balls in Bag E is 330. Therefore, 44% of the total balls in Bag E equals 330.
Let $T_E$ be the total number of balls in Bag E:

$44\%\text{of}{T}_E=330$

$0.44\times T_E=330$

$T_E=\frac{330}{0.44}=750$

Now we calculate the individual counts of red and blue balls in Bag E:
Number of red balls in E ($R_E$):

$R_E=72\%\text{of}750=540$

Number of blue balls in E ($B_E$):

$B_E=750-540=210$

3. Calculating the Combined Percentage:
Total number of red balls in A and E together:

$R_A+R_E=150+540=690$

Total number of blue balls in A and E together:

$B_A+B_E=90+210=300$

The percentage of red balls in A and E together with respect to blue balls in A and E together is:

$\left(\frac{690}{300}\right)\times 100\%=2.3\times 100\%=230\%$

Therefore, the number of red balls in bags A and E together is 230% of the number of blue balls in A and E together.