The total number of petrol cars sold by E is 33.33% more than that of the total number of EV cars sold by C. If the total number of diesel cars sold by E is two-fifths of the total number of petrol cars sold by D and the total number of cars sold by E is two times that of A, then find the difference between the total number of EV cars sold by E and the total number of diesel cars sold by C.

Read the following table carefully and answer the questions given below. The table shows the total number of cars (EV, Diesel and petrol) sold and the percentage of EV cars sold out of the total cars sold by four different companies. The table also shows the difference between the petrol and diesel cars sold by these four companies.

Note: Petrol cars sold are more than the diesel cars sold by each company .

Companies	Total number of cars sold	Percentage of EV cars sold	Difference between the petrol and the diesel cars sold
A	400	25%	70
B	550	10%	85
C	360	30%	52
D	280	15%	102

The correct answer is 488.

Let us solve the problem step-by-step.

First, we analyze the data given in the table for each company (A, B, C, and D) and the note.
Note: Petrol cars sold > Diesel cars sold for each company.
Let $EV$ be the number of EV cars, $P$ be the number of petrol cars, and $Ds$ be the number of diesel cars sold.
For any company, the total number of cars sold is:
$\text{Total}=EV+P+Ds$

Let's calculate the details for Company C:
Total cars sold by C = 360
Percentage of EV cars sold by C = 30%
Therefore, the number of EV cars sold by C is:
$E{V}_C=360\times 30\%=108$
The remaining cars (Petrol + Diesel) sold by C is:
$P_C+D{s}_C=360-108=252$
The difference between petrol and diesel cars sold by C is 52. Since petrol cars sold are more than diesel cars:
$P_C-D{s}_C=52$
Adding the two equations:
$2P_C=252+52=304\Rightarrow P_C=152$
Subtracting the equations:
$2D{s}_C=252-52=200\Rightarrow D{s}_C=100$

Let's calculate the details for Company D:
Total cars sold by D = 280
Percentage of EV cars sold by D = 15%
Number of EV cars sold by D is:
$E{V}_D=280\times 15\%=42$
The remaining cars (Petrol + Diesel) sold by D is:
$P_D+D{s}_D=280-42=238$
The difference between petrol and diesel cars sold by D is 102:
$P_D-D{s}_D=102$
Adding these two equations:
$2P_D=238+102=340\Rightarrow P_D=170$

Now, let us find the details for Company E using the given relationships:
1) The total number of petrol cars sold by E is 33.33% more than that of the total number of EV cars sold by C.
Note that 33.33% is equivalent to $\frac{1}{3}$.
$P_E=E{V}_C\times (1+\frac{1}{3})=108\times \frac{4}{3}=36\times 4=144$
2) The total number of diesel cars sold by E is two-fifths ($\frac{2}{5}$) of the total number of petrol cars sold by D.
$D{s}_E=\frac{2}{5}\times P_D=\frac{2}{5}\times 170=2\times 34=68$
3) The total number of cars sold by E is two times that of A.
Total cars sold by A = 400
Therefore, Total cars sold by E is:
${\text{Total}}_E=2\times 400=800$

Now we can determine the number of EV cars sold by E:
$E{V}_E={\text{Total}}_E-(P_E+D{s}_E)$
$E{V}_E=800-(144+68)=800-212=588$

Finally, we calculate the difference between the total number of EV cars sold by E and the total number of diesel cars sold by C:
$\text{Difference}=E{V}_E-D{s}_C$
$\text{Difference}=588-100=488$