Directions: Study the table given below carefully and answer the question that follows.

The table displays the total workforce and the percentage of female employees across four different company branches.

Note: The number of male employees in Branch P is 700, and the total number of female employees in Branches Q and S together is 945.

$\begin{array}{ccc}\text{Branch}& \text{Total workforce}& \text{Percentage of females}\\ P& 800& X\%\\ Q& 1200& 60\%\\ R& 500& 40\%\\ S& 900& Y\%\end{array}$

The combined count of male employees in Branches Q and R is what percentage greater or smaller than the total number of female employees in Branch S?

The correct answer is 246.67%.

Step 1: Find the number of male employees in Branch Q.

Total workforce in Branch Q = 1200
Percentage of female employees in Branch Q = 60%

Number of female employees in Branch Q = $\frac{60}{100}\times 1200=720$

Number of male employees in Branch Q = $1200-720=480$

Step 2: Find the number of male employees in Branch R.

Total workforce in Branch R = 500
Percentage of female employees in Branch R = 40%

Number of female employees in Branch R = $\frac{40}{100}\times 500=200$

Number of male employees in Branch R = $500-200=300$

Step 3: Calculate the combined count of male employees in Branches Q and R.

Combined male workforce (Q + R) = $480+300=780$

Step 4: Find the total number of female employees in Branch S.

Given that the total number of female employees in Branches Q and S together is 945:

Females in Q + Females in S = 945
720 + Females in S = 945

Number of female employees in Branch S = $945-720=225$

Step 5: Calculate the required percentage.

Difference between combined males (Q + R) and females in S = $780-225=555$

Percentage greater = $\frac{555}{225}\times 100=246.67\%$