Question Details

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Train P passes a signal post in 15 seconds and clears a 200-metre platform in 25 seconds. How long will Train P take to pass Train Q, which is 420 metres long and travels at 90 km/hr in the opposite direction?

Options

A

18 seconds

B

20 seconds

C

16 seconds

D

14 seconds

E

24 seconds

Show Answer

Correct Answer :

Option C

16 seconds

Solution :

The correct answer is 16 seconds.

Step 1: Find the speed and length of Train P.

When a train passes a signal post, the distance covered is equal to the length of the train itself. Let the length of Train P be LP metres and its speed be vP m/s.


LP = vP × 15

When Train P clears a 200-metre platform, the total distance covered is the sum of the length of the train and the platform length, which takes 25 seconds:


LP + 200 = vP × 25

Subtracting the first equation from the second equation:


( LP + 200 ) - LP = 25 vP - 15 vP

200 = 10 vP

vP = 200 10 = 20 m/s

Now, calculate the length of Train P:


LP = 20 × 15 = 300 metres

Step 2: Convert the speed of Train Q to metres per second (m/s).

The speed of Train Q is given as 90 km/hr. To convert km/hr to m/s, multiply by 518:


Speed of Train Q = 90 × 5 18 = 25 m/s

Step 3: Calculate the relative speed and total distance to cross each other.

Since the two trains are travelling in opposite directions, their relative speed is the sum of their individual speeds:


Relative Speed = 20 + 25 = 45 m/s

The total distance to be covered when passing each other is the sum of the lengths of both trains:


Total Distance = 300 + 420 = 720 metres

Step 4: Calculate the time taken to pass Train Q.

Using the formula Time=Total DistanceRelative Speed:


Time taken = 720 45 = 16 seconds

Thus, Train P will take 16 seconds to pass Train Q.

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