What approximate value come in the place of ‘x’ in the following questions.

${24.21}^2+12.16=?\times (49.99\%\text{ of}\mathrm{ 55.98})$

To find the approximate value of $x$ in the given equation, we can round each decimal number to its nearest integer or easy-to-calculate value.

The given equation is:
${24.21}^2+12.16=x\times (49.99\%\text{of}55.98)$

Step 1: Simplify the Left-Hand Side (LHS)
We approximate the numbers on the left-hand side:
$24.21\approx 24$
$12.16\approx 12$

Now, calculate the value:
${24}^2=576$
Adding 12 to this value gives:
$576+12=588$

So, the LHS is approximately $588$.

Step 2: Simplify the Right-Hand Side (RHS)
Next, we approximate the terms inside the parentheses:
$49.99\%\approx 50\%$
$55.98\approx 56$

Now, find $50\%$ of $56$:
$50\%\text{of}56=0.5\times 56=28$

So, the RHS becomes:
$x\times 28$

Step 3: Solve for $x$
Equating the LHS and RHS:
$588=x\times 28$
$x=\frac{588}{28}$
$x=21$

Therefore, the approximate value that comes in place of 'x' is 21.