Find the integer portion of the numerical value of the expression E = $\sqrt{49}+\sqrt{48}$.

The correct option is 13.

We are given the expression:

$E=\sqrt{49}+\sqrt{48}$

Step 1: Simplify the known square root.
We know that:
$7^2=49$
Therefore:
$\sqrt{49}=7$

Step 2: Estimate the value of the second square root.
The number 48 lies between the perfect squares 36 and 49:
$36<48<49$
Taking the square root across all terms:
$\sqrt{36}<\sqrt{48}<\sqrt{49}$
Simplifying the square roots:
$6<\sqrt{48}<7$

Step 3: Determine the range of the full expression.
Rewrite the expression as:
$E=7+\sqrt{48}$
Add 7 to all parts of the inequality:
$7+6<7+\sqrt{48}<7+7$
$13<E<14$

Conclusion:
Since the value of
$E$
lies strictly between 13 and 14, its integer portion is 13.