What is X in the sequence?
132, 129, 124, 117, 106, 93, X

The correct option is 76.

To find the value of $X$ in the sequence, let us analyze the differences between consecutive terms in the sequence:

132, 129, 124, 117, 106, 93, X

Let's calculate the difference between each term and the next one:

First to second term: $132-129=3$
Second to third term: $129-124=5$
Third to fourth term: $124-117=7$
Fourth to fifth term: $117-106=11$
Fifth to sixth term: $106-93=13$

The sequence of differences we subtracted is: 3, 5, 7, 11, 13.

We can see that these numbers (3, 5, 7, 11, 13) are consecutive prime numbers in increasing order.

Following this pattern, the next prime number after 13 is 17. Therefore, to find the next term $X$, we must subtract 17 from the last known term, 93:

$X=93-17=76$