${31}^2-\sqrt{169}=62\%\text{of}?+{24}^2$

What should come in place of question mark (?) in the following questions?

The correct answer is 600.

Let the unknown value in place of the question mark (?) be $x$.

We are given the equation:

${31}^2-\sqrt{169}=62\%\text{of}x+{24}^2$

Step 1: Simplify the individual terms.
First, calculate the square of 31:
${31}^2=961$

Next, calculate the square root of 169:
$\sqrt{169}=13$

Next, calculate the square of 24:
${24}^2=576$

Step 2: Substitute the simplified values back into the equation.
$961-13=\frac{62}{100}\times x+576$

Simplify the left-hand side:
$948=0.62x+576$

Step 3: Solve for $x$.
Subtract 576 from both sides of the equation:
$948-576=0.62x$

$372=0.62x$

Divide both sides by 0.62:
$x=\frac{372}{0.62}$

$x=\frac{37200}{62}$

$x=600$

Therefore, the number that should come in place of the question mark is 600.