What will come in the place of question (?) mark in following the question:

$\frac{180\times 18\times 2}{60\times 12}-1={?}^3$

To find the value that should replace the question mark (?), let us write down the given equation:
$\frac{180\times 18\times 2}{60\times 12}-1={?}^3$

Let the unknown value in place of the question mark be $x$. The equation becomes:
$\frac{180\times 18\times 2}{60\times 12}-1=x^3$

Step 1: Simplify the fraction in the equation.
First, we can simplify $\frac{180}{60}$:
$\frac{180}{60}=3$

Now, substitute this back into the expression:
$\frac{3\times 18\times 2}{12}-1=x^3$

Step 2: Simplify the remaining terms in the fraction.
We know that $3\times 2=6$. So the numerator becomes:
$6\times 18=108$

Now, divide 108 by 12:
$\frac{108}{12}=9$

Step 3: Substitute the simplified value back into the equation:
$9-1=x^3$
$8=x^3$

Step 4: Solve for $x$ by taking the cube root of both sides:
$x=\sqrt[3]{8}$
$x=2$

Therefore, the value that will come in place of the question mark is 2.