What will come in the place of question (?) mark in following the question:

$\frac{180\times 18\times 2}{60\times 12}-1={?}^3$

The correct answer is 2.

To find the value that should replace the question mark (?), we begin with the given equation:
$\frac{180\times 18\times 2}{60\times 12}-1={?}^3$

Step 1: Simplify the fractional part of the equation.
Let us evaluate the expression:
$\frac{180\times 18\times 2}{60\times 12}$
We can simplify the expression by canceling common factors between the numerator and the denominator:
First, divide 180 by 60:
$\frac{180}{60}=3$
Now, the fraction becomes:
$\frac{3\times 18\times 2}{12}$
Next, multiply 18 by 2 in the numerator:
$18\times 2=36$
This simplifies the fraction to:
$\frac{3\times 36}{12}$
Now, divide 36 by 12:
$\frac{36}{12}=3$
Finally, multiply the remaining numbers:
$3\times 3=9$

Step 2: Substitute the simplified fraction value back into the original equation.
Substituting 9 for the fractional term gives:
$9-1={?}^3$
$8={?}^3$

Step 3: Solve for the question mark (?).
To find the value of ?, we take the cube root of both sides:
$?=\sqrt[3]{8}$
Since $2^3=8$, we find:
$?=2$