Question Details

Which compound is optically inactive out of following

(I) n-propyl chloride

(II) secondary butyl chloride

(III) tert butyl chloride, (IV) isopropyl chloride.

Options

A

Only I, III, IV

B

Only IV

C

Only I, II, III

D

Only II, III, IV

Show Answer

Correct Answer :

Option A

Only I, III, IV

Solution :

The correct option is Only I, III, IV.


Understanding Optical Activity and Chirality:

A organic molecule is optically active if it contains at least one chiral carbon atom (a stereocenter) and lacks a plane or center of symmetry. A chiral carbon is defined as a tetrahedral carbon atom bonded to four completely different groups or atoms.

If a molecule does not have any chiral carbon atom (or is superimposable on its mirror image), it is achiral and therefore optically inactive.


Analyzing Each Compound:

(I) n-propyl chloride:

Chemical structure: CH3-CH2-CH2-Cl

- C-1 is attached to 2 hydrogen atoms, 1 chlorine atom, and 1 ethyl group.
- C-2 is attached to 2 hydrogen atoms, 1 methyl group, and 1 chloromethyl group.
- C-3 is attached to 3 hydrogen atoms.

None of the carbon atoms are attached to four different groups. Therefore, n-propyl chloride has no chiral center and is optically inactive.


(II) secondary butyl chloride (sec-butyl chloride):

Chemical structure: CH3-CH(Cl)-CH2-CH3

- C-2 is attached to four distinct groups: a hydrogen atom (-H), a chlorine atom (-Cl), a methyl group (-CH3), and an ethyl group (-CH2CH3).

Because C-2 is a chiral carbon, secondary butyl chloride is chiral and is optically active.


(III) tert-butyl chloride:

Chemical structure: (CH3)3C-Cl

- The central carbon atom is bonded to three identical methyl groups (-CH3) and one chlorine atom (-Cl).

Since three of the four groups are identical, there is no chiral center. Thus, tert-butyl chloride is optically inactive.


(IV) isopropyl chloride:

Chemical structure: (CH3)2CH-Cl

- The central carbon atom is attached to two identical methyl groups (-CH3), one hydrogen atom (-H), and one chlorine atom (-Cl).

Since it has two identical groups attached to the central carbon, it lacks a chiral carbon and is optically inactive.


Conclusion:

Compounds I (n-propyl chloride), III (tert-butyl chloride), and IV (isopropyl chloride) do not possess any chiral carbon atoms and are optically inactive.

Hence, the optically inactive compounds are Only I, III, IV.

Unlock Our Free Library

Access expert-curated educational resources and study materials—completely free.

Discover more resources

You may also like

Mock Tests

View All
  • JEE
  • intermediate
  • 3 hours
  • chemistry, mathematics, physics
  • Proctored

  • JEE
  • intermediate
  • 3 hours
  • chemistry, mathematics, physics

Ask AI Tutor
5 left
Q1 View Question & Options
AI Tutor is solving this question...
Reading question context & options...