Which compound is optically inactive out of following
(I) n-propyl chloride
(II) secondary butyl chloride
(III) tert butyl chloride, (IV) isopropyl chloride.
Correct Answer :
Only I, III, IV
Solution :
The correct option is Only I, III, IV.
Understanding Optical Activity and Chirality:
A organic molecule is optically active if it contains at least one chiral carbon atom (a stereocenter) and lacks a plane or center of symmetry. A chiral carbon is defined as a tetrahedral carbon atom bonded to four completely different groups or atoms.
If a molecule does not have any chiral carbon atom (or is superimposable on its mirror image), it is achiral and therefore optically inactive.
Analyzing Each Compound:
(I) n-propyl chloride:
Chemical structure: CH3-CH2-CH2-Cl
- C-1 is attached to 2 hydrogen atoms, 1 chlorine atom, and 1 ethyl group.
- C-2 is attached to 2 hydrogen atoms, 1 methyl group, and 1 chloromethyl group.
- C-3 is attached to 3 hydrogen atoms.
None of the carbon atoms are attached to four different groups. Therefore, n-propyl chloride has no chiral center and is optically inactive.
(II) secondary butyl chloride (sec-butyl chloride):
Chemical structure: CH3-CH(Cl)-CH2-CH3
- C-2 is attached to four distinct groups: a hydrogen atom (-H), a chlorine atom (-Cl), a methyl group (-CH3), and an ethyl group (-CH2CH3).
Because C-2 is a chiral carbon, secondary butyl chloride is chiral and is optically active.
(III) tert-butyl chloride:
Chemical structure: (CH3)3C-Cl
- The central carbon atom is bonded to three identical methyl groups (-CH3) and one chlorine atom (-Cl).
Since three of the four groups are identical, there is no chiral center. Thus, tert-butyl chloride is optically inactive.
(IV) isopropyl chloride:
Chemical structure: (CH3)2CH-Cl
- The central carbon atom is attached to two identical methyl groups (-CH3), one hydrogen atom (-H), and one chlorine atom (-Cl).
Since it has two identical groups attached to the central carbon, it lacks a chiral carbon and is optically inactive.
Conclusion:
Compounds I (n-propyl chloride), III (tert-butyl chloride), and IV (isopropyl chloride) do not possess any chiral carbon atoms and are optically inactive.
Hence, the optically inactive compounds are Only I, III, IV.
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