Question Details

Which of the following differential equations is/are nonlinear ?

Options

A

t x ( t ) + d x ( t ) d t = t 2 e t , x ( 0 ) = 0

B

1 2 e t + x ( t ) d x ( t ) d t = 0 , x ( 0 ) = 0

C

x ( t ) cos t d x ( t ) d t sin t = 1 , x ( 0 ) = 0

D

x ( t ) + e ( d x ( t ) d t ) = 1 , x ( 0 ) = 0

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Correct Answer :

Option B

1 2 e t + x ( t ) d x ( t ) d t = 0 , x ( 0 ) = 0

Option D

x ( t ) + e ( d x ( t ) d t ) = 1 , x ( 0 ) = 0

Solution :

To determine which of the given differential equations are nonlinear, let us first define the criteria for a differential equation to be linear.

An ordinary differential equation of order n for the dependent variable x(t) with respect to the independent variable t is linear if it can be written in the form:
an(t) dnx dtn + an-1(t) dn-1x dtn-1 + + a1(t) dx dt + a0(t) x = g(t)
This definition implies two essential conditions for linearity:
1. The dependent variable x and all its derivatives must be raised to the first power only.
2. There must be no products of the dependent variable x and/or its derivatives (e.g., no terms like xdxdt or (dxdt)2).
3. The dependent variable x and its derivatives must not be arguments of nonlinear functions (e.g., no terms like ex, sin(x), or edx/dt).

Let us evaluate each of the given options against these criteria:

1. Option 1:
t x ( t ) + d x ( t ) d t = t 2 e t
Here, both x(t) and its first derivative dxdt are of first degree. The coefficients t and 1 depend only on the independent variable t. Therefore, this equation is linear.

2. Option 2:
1 2 e t + x ( t ) d x ( t ) d t = 0
This equation contains the term x(t)dxdt, which is a product of the dependent variable x and its derivative. Because of this product term, the equation is nonlinear.

3. Option 3:
x ( t ) cos t d x ( t ) d t sin t = 1
Here, x(t) and dxdt are both of first degree, and their coefficients cost and sint are functions only of the independent variable t. Therefore, this equation is linear.

4. Option 4:
x ( t ) + e ( d x ( t ) d t ) = 1
This equation contains the term e(dx/dt), which is an exponential function of a derivative of the dependent variable. Since the derivative is inside a transcendental/nonlinear function, this equation is nonlinear.

Thus, the nonlinear differential equations are:
1 2 e t + x ( t ) d x ( t ) d t = 0 , x ( 0 ) = 0 and
x ( t ) + e ( d x ( t ) d t ) = 1 , x ( 0 ) = 0

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