Question Details

Which reaction is NOT a redox reaction?

Options

A

Zn + CuSO4 → ZnSO4 + Cu

B

2KClO3 + I2 → 2KIO3 + Cl2

C

H2 + Cl2 → 2HCl

D

BaCl2 + Na2SO4 → BaSO4 + 2NaCl

Show Answer

Correct Answer :

Option D

BaCl2 + Na2SO4 → BaSO4 + 2NaCl

BaCl2 + Na2SO4 → BaSO4 + 2NaCl

Solution :

The correct answer is: BaCl2 + Na2SO4 → BaSO4 + 2NaCl

A redox (reduction-oxidation) reaction is a chemical reaction that involves a transfer of electrons between chemical species. This transfer is detected by a change in the oxidation states (oxidation numbers) of the atoms involved in the reaction.

Let's analyze the oxidation states of the elements in each of the given reactions to determine which one is not a redox reaction:

1. Zn + CuSO4 → ZnSO4 + Cu
- Zinc (Zn) changes its oxidation state from 0 in its elemental form to +2 in ZnSO4 (oxidation).
- Copper (Cu) changes its oxidation state from +2 in CuSO4 to 0 in its elemental form (reduction).
Since there are changes in oxidation states, this is a redox reaction.

2. 2KClO3 + I2 �� 2KIO3 + Cl2
- Iodine (I) changes its oxidation state from 0 in I2 to +5 in KIO3 (oxidation).
- Chlorine (Cl) changes its oxidation state from +5 in KClO3 to 0 in Cl2 (reduction).
Since there are changes in oxidation states, this is a redox reaction.

3. H2 + Cl2 → 2HCl
- Hydrogen (H) changes its oxidation state from 0 in H2 to +1 in HCl (oxidation).
- Chlorine (Cl) changes its oxidation state from 0 in Cl2 to -1 in HCl (reduction).
Since there are changes in oxidation states, this is a redox reaction.

4. BaCl2 + Na2SO4 → BaSO4 + 2NaCl
Let us look at the oxidation state of each element before and after the reaction:
- Barium (Ba): Remains at +2 in both BaCl2 and BaSO4.
- Chlorine (Cl): Remains at -1 in both BaCl2 and NaCl.
- Sodium (Na): Remains at +1 in both Na2SO4 and NaCl.
- Sulfur (S): Remains at +6 in the sulfate ion (SO42-) on both sides.
- Oxygen (O): Remains at -2 in the sulfate ion (SO42-) on both sides.
Because none of the atoms change their oxidation states during the process, this is a double displacement (precipitation) reaction rather than a redox reaction.

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